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Active Calculus - Multivariable

Activity 11.7.3.
Let’s consider the function \(f\) defined by \(f(x,y) = \frac{1}{3}(x^2-y^2)\text{.}\) Some contours for this function are shown in Figure 11.7.14.
Figure 11.7.14. A contour plot of \(f(x,y)=\frac{1}{3}(x^2-y^2)\)
(a)
Find the gradient \(\nabla f (x,y)\text{.}\)
(b)
For each of the following points \((x_0,y_0)\text{,}\) evaluate the gradient \(\nabla f(x_0,y_0)\) and sketch the gradient vector with its tail at \((x_0,y_0)\text{.}\) Some of the vectors are too long to fit onto the plot, but we’d like to draw them to scale; to do so, scale each vector by a factor of 1/2.
  • \(\displaystyle (x_0,y_0) = (2,0)\)
  • \(\displaystyle (x_0,y_0) = (0,2)\)
  • \(\displaystyle (x_0,y_0) = (2,2)\)
  • \(\displaystyle (x_0,y_0) = (2,1)\)
  • \(\displaystyle (x_0,y_0) = (-3,2)\)
  • \(\displaystyle (x_0,y_0) = (-2,-4)\)
  • \(\displaystyle (x_0,y_0) = (0,0)\)
(c)
Write a few sentences about how the direction of the gradient at each of these points is related to the the contour passing through that point.
(d)
Does the output of \(f\) increase or decrease in the direction of \(\nabla f(x_0,y_0)\text{?}\) Write a few sentences and use examples from the points above to justify your answer.