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Active Calculus - Multivariable

Section 12.1 Double Riemann Sums and Double Integrals over Rectangles

Subsection 12.1.1 Introduction

In single-variable calculus, recall that we used the classic calculus approach to define the definite integral as the area under a graph. Specifically, we approximated the area under the graph of a positive function \(f\) on an interval \([a,b]\) by adding areas of rectangles whose heights are determined by the curve. We then broke the interval \([a,b]\) into smaller subintervals, constructing rectangles on each of these smaller intervals to approximate the region under the curve on that subinterval, then summing the areas of these rectangles to approximate the area under the curve. We defined the definite integral of \(f\) using the limit of this Riemann sum as the size of all of the subintervals goes to zero.
In the Preview Activity, we will review a few ideas from integrals in single variable calculus. The rest of this section will then be used to extend the ideas of integration and its interpretations to functions of two variables over a rectangular region.

Preview Activity 12.1.1.
(a)
A plot of \(f\) for inputs in the interval \([0,2]\) is shown in Figure 12.1.1. Break the interval \([0,2]\) into four equally sized subintervals and draw the rectangles that would be used to construct a Riemann sum to approximate the area under \(f\) on the interval \([0,2]\text{.}\) You can use whichever point you want on each subinterval to evaluate the height the of the rectangles.
Figure 12.1.1.
(b)
Estimate the heights of the rectangles used in your Riemann sum above to estimate \(\displaystyle{\int_0^2 f(x)\enspace dx}\text{.}\) Write a couple of sentences about why you think your estimate for the definite integral of \(f\) is either an overestimate, an underestimate, or close to the true value.
(c)
Explain why it doesn’t matter what method (left endpoint, right endpoint, midpoint, etc.) you use for selecting which point is evaluated on each of the subintervals in the definition of the definite integral.
\begin{equation*} \int_a^b f(x) \enspace dx = \lim_{\Delta x_i \to 0} \sum_{i=1}^n f(x_i^*)\Delta x_i \end{equation*}
(d)
For each of the following functions plotted below, determine if the definite integral over the region shown will be positive, negative, or zero and write a sentence to justify your answer.
Figure 12.1.2.
Figure 12.1.3.
Figure 12.1.4.
In this section, we will use the classic calculus approach to define and understand the definite integral for a function of two variables over a rectangular region of inputs. Just as you did in single variable calculus, we will develop some algebraic rules to help efficiently evaluate these integrals. Later in this chapter we will will generalize to regions that are not rectangular and work with functions of three or more variables.

Subsection 12.1.2 Double Riemann Sums over Rectangles

The motivating interpretation of a definite integral for a function of one variable was the area under a curve (over a particular interval of inputs). We will use the same motivating interpretation for the definite integral of function of two variables; The definite integral of a function of two variables will measure the size of the region beneath the graph of \(f\) over a set of inputs. We can show this geometrically as the volume of the region below the surface given by \(z=f(x,y)\) as shown in Figure 12.1.5. The surface given by \(z=f(x,y)\) is shown in blue and the set of inputs we want to look at is shown (on the \(xy\)-plane) in red. The double integral of \(f\) over the red region should measure the volume of the region shaded in gray.
Figure 12.1.5. A plot of the volume under as surface \(z=f(x,y)\) over a region \(R\text{,}\) in red
The region of integration shown shaded red in Figure 12.1.5 is irregular in our coordinates (\(x\) and \(y\)) and we will explore this kind of problem in Section 12.3 once we have some intuition and tools from examining rectangular regions of integration.
We will apply our classic calculus approach to the region shown in Figure 12.1.6. In particular, we have a rectangular region of inputs to examine and we want to
  1. estimate the volume between the surface plot (in blue) and the \(xy\)-plane
  2. quantify how our estimate for the region under the graph of \(f(x,y)\) changes when we use a smaller scale
  3. use a limit to evaluate the true value of the volume under the surface
To estimate the volume under our graph, we will use rectangular prisms because their volume is easy to compute:
\begin{equation*} \text{Volume of rectangular prism}= (\text{length})(\text{width})(\text{height}) \end{equation*}
In the next activity, we will go through these steps for a particular function and rectangular region of integration as well as introduce some of the notation used in our development of double integrals.
Figure 12.1.6. A plot of the volume under a surface over a rectangular region

Activity 12.1.2.
In this activity, we will be going through the first two steps of the classic calculus approach to defining the definite integral of \(f(x,y) = 100 - x^2-y^2\) on the rectangular domain \(R = [0,8] \times [2,6]\text{.}\) Remember that we are trying to measure the volume below the graph of \(f\) over the region \(R\text{,}\) so we will start with estimating this volume.
(a)
We want to understand the numerical calculations involved in the classic calculus approach, so we will not look a graph of \(z=f(x,y)\text{,}\) but we will need to understand our region of integration. On Figure 12.1.7, outline \(R\text{,}\) the rectangle that corresponds to the region of integration.
Figure 12.1.7.
(b)
Because all of the regions and subregions we are looking at will be rectangles, we can break up the \(x\) and \(y\) coordinates into pieces separately. We will break the interval of \(x\)-coordinates into four equally sized subintervals and we will break the interval of \(y\)-coordinates into three equally sized subintervals. How large will the subintervals be in the \(x\)-direction and the \(y\)-direction?
(c)
Let \(\Delta x_i\) be the \(i\)-th subinterval for \(x\text{.}\) We want to state the endpoints of each of the \(\Delta x_i\text{.}\) The first subinterval, \(\Delta x_1\text{,}\) will go from \(x_0\) to \(x_1\text{,}\) the second subinterval, \(\Delta x_2\text{,}\) will go from \(x_1\) to \(x_2\text{,}\) the third subinterval, \(\Delta x_3\text{,}\) will go from \(x_2\) to \(x_3\text{,}\) and the fourth subinterval, \(\Delta x_4\text{,}\) will go from \(x_3\) to \(x_4\text{.}\)
Give the values for \(x_0\text{,}\) \(x_1\text{,}\) \(x_2\text{,}\) \(x_3\text{,}\) and \(x_4\) and add these as tick marks on the \(x\)-axis of Figure 12.1.7 to make sure your subintervals are equally sized.
(d)
Let \(\Delta y_i\) be the \(i\)-th subinterval for \(y\text{.}\) Give the values for \(y_0\text{,}\) \(y_1\text{,}\) \(y_2\text{,}\) and \(y_3\) and add these as tick marks on the \(y\)-axis of Figure 12.1.7 to make sure your subintervals are equally sized.
(e)
Now that we have our subintervals in \(x\) and \(y\) coordinates, we want to state the smaller rectangles we will use for our approximation. Let \(R_{i j}\) be the rectangle corresponding to \(\Delta x_i \times \Delta y_j\text{.}\)
  1. How many smaller rectangles are there in our partition?
  2. Outline each of the smaller rectangles on Figure 12.1.7 and label each rectangle as either \(R_{1 1}, R_{1 2} , ...\text{.}\)
  3. Let \(\Delta A\) be the area of each of these smaller rectangles (\(R_{i j}\)). \(\Delta A = \)
(f)
We will estimate the height of each of the rectangular prisms over our \(R_{i j}\) by evaluating \(f\) at the upper right point of each smaller rectangle. State the point at the upper right of each smaller rectangle and evaluate \(f\) at each of these points.
(g)
Write a sentence about why the volume of our approximation on each smaller rectangle would be
\begin{equation*} f(x_i,y_j) \Delta A \end{equation*}
then write a couple sentences about how you would find your approximation of the volume under the surface \(z=f(x,y)\) over the region \(R\text{.}\) (You do not need to do this calculation but rather explain what calculation is being done.)
(h)
We used the upper right point to approximate the heights of our rectangular prisms on each \(R_{i j}\text{.}\) Write a sentence or two about whether you think the upper right point provides an overestimate, an underestimate, or approximately the average value for \(f\) on each \(R_{i j}\text{.}\) Explain how this suggests that your estimate for the volume under the surface \(z=f(x,y)\) over the region \(R\) is either an overestimate, an underestimate, or approximately the correct value.

Subsection 12.1.3 Double Riemann Sums and Double Integrals

Every part of the previous activity can be generalized to work on any finite rectangular region and any number of subintervals (in either the \(x\) or \(y\) directions), so we will state these steps in general below and note that using more subintervals corresponds to estimating on a smaller scale (step 2 of the classic calculus approach!).

Definition 12.1.8.

Let \(f\) be a continuous function on a rectangle \(R = \{(x,y) : a \leq x \leq b, c \leq y \leq d\}\text{.}\) A double Riemann sum for \(f\) over \(R\) is created as follows.
  1. Partition the interval \([a, b]\) into \(m\) subintervals of equal length \(\Delta x = \frac{b-a}{m}\text{.}\) Let \(x_0\text{,}\) \(x_1\text{,}\) \(\ldots\text{,}\) \(x_m\) be the endpoints of these subintervals, where \(a = x_0\lt x_1\lt x_2 \lt \cdots \lt x_m = b\text{.}\)
  2. Partition the interval \([c, d]\) into \(n\) subintervals of equal length \(\Delta y = \frac{d-c}{n}\text{.}\) Let \(y_0\text{,}\) \(y_1\text{,}\) \(\ldots\text{,}\) \(y_n\) be the endpoints of these subintervals, where \(c = y_0\lt y_1\lt y_2 \lt \cdots \lt y_n = d\text{.}\)
  3. These two partitions create a partition of the rectangle \(R\) into \(mn\) subrectangles \(R_{ij}\) with opposite vertices \((x_{i-1},y_{j-1})\) and \((x_i, y_j)\) for \(i\) between \(1\) and \(m\) and \(j\) between \(1\) and \(n\text{.}\) These rectangles all have equal area \(\Delta A = \Delta x \cdot \Delta y\text{.}\)
  4. Choose a point \((x_{ij}^*, y_{ij}^*)\) in each rectangle \(R_{ij}\text{.}\) Then, a double Riemann sum for \(f\) over \(R\) is given by
    \begin{equation*} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \cdot \Delta A. \end{equation*}
If \(f(x,y) \geq 0\) on the rectangle \(R\text{,}\) we may ask to find the volume of the solid bounded above by \(f\) over \(R\text{,}\) as illustrated in Figure 12.1.9.
Figure 12.1.9. The volume below a surface \(z=f(x,y)\) over a rectangular region (shown in red)
This volume is approximated by a Riemann sum, which sums the volumes of the rectangular prisms shown in Figure 12.1.10. As we let the number of subrectangles increase without bound (in other words, as both \(m\) and \(n\) go to infinity in a double Riemann sum), as illustrated in Figure 12.1.10, the sum of the volumes of the rectangular boxes approaches the true volume of the solid bounded above by \(z=f(x,y)\) over the region \(R\text{.}\) You can use the sliders at the top of Figure 12.1.10 to change the number of subintervals used in the Riemann sum and verify geometrically how the estimated volume will approach true volume under \(f\) as \(n\) and \(m\) become arbitrarily large. The value of this limit (the third step in our classic calculus approach), provided it exists, is the double integral we have been seeking.
Figure 12.1.10. The estimated volume under a surface \(z=f(x,y)\) when using \(m\) by \(n\) subrectangles

Definition 12.1.11.

Let \(R\) be a rectangular region in the \(xy\)-plane and \(f\) a continuous function over \(R\text{.}\) With terms defined as in a double Riemann sum, the double integral of \(f\) over \(R\) is
\begin{equation*} \iint_R f(x,y) \, dA = \lim_{m,n \to \infty} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \cdot \Delta A. \end{equation*}

Aside

Before we move on to the interpretations of double integrals, we will talk about a couple of simplifying ideas used in our development of the double integral that are not strictly necessary. Many times we will use equally sized subintervals or pieces of our region of integration but that is not strictly necessary. The most general form of a double integral would just require that as we take the limit, the area of every smaller piece must go to zero. In Activity 12.1.2, we used the upper right point of each smaller rectangle to evaluate \(f\) but in Definition 12.1.11 there is not a particular point in each smaller rectangle used. Remember that as the area of all the smaller rectangles is going to zero, there will be smaller and smaller differences between the output of \(f\) on the points in the smaller rectangle.

Subsection 12.1.4 Interpretation of Double Riemann Sums and Double integrals

At the moment, there are three ways we can interpret the value of the double integral, where each of these corresponds to the same three interpretations of integrals from single variable calculus: the area under the curve, the average value of the function, and the accumulation of some density function.
  • Suppose that \(f(x,y)\) assumes both positive and negatives values on the rectangle \(R\text{,}\) as shown in Figure 12.1.12. When constructing a Riemann sum, for each \(i\) and \(j\text{,}\) the product \(f(x_{ij}^*, y_{ij}^*) \enspace \Delta A\) can be interpreted as a “signed” volume of a box with base area \(\Delta A\) and “signed” height \(f(x_{ij}^*, y_{ij}^*)\text{.}\) Since \(f\) can have negative values, this “height” could be negative. The sum
    \begin{equation*} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \enspace \Delta A \end{equation*}
    can then be interpreted as a sum of “signed” volumes of boxes, with a negative sign attached to those boxes whose heights are below the \(xy\)-plane.
    Figure 12.1.12. A plot of the surface \(z=f(x,y)\) over the rectangular region \(R\)
    We can then realize the double integral \(\iint_R f(x,y) \, dA\) as a difference in volumes: \(\iint_R f(x,y) \, dA\) tells us the volume of the solids the graph of \(f\) bounds above the \(xy\)-plane over the rectangle \(R\) minus the volume of the solids the graph of \(f\) bounds below the \(xy\)-plane under the rectangle \(R\text{.}\) This is shown in Figure 12.1.13.
    Figure 12.1.13. A plot of the signed volume with the volume above the \(xy\)-plane shown in blue and the volume below the \(xy\)-plane shown in red
    The double integral of \(f\) over the rectangle \(R\) will be positive because there is more blue volume (volume above the \(xy\)-plane) than red volume (volume below the \(xy\)-plane, which is counted as negative.)
  • The average of the finitely many (\(mn\)) values \(f(x_{ij}^*, y_{ij}^*)\) that we take in a double Riemann sum is given by
    \begin{equation*} \mbox{Avg} _{mn} = \frac{1}{mn} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*). \end{equation*}
    If we take the limit as \(m\) and \(n\) go to infinity, we obtain what we can define as the average value of \(f\) over the region \(R\text{,}\) which is connected to the value of the double integral. First, to view \(\text{ Avg } _{mn}\) as a double Riemann sum, note that
    \begin{equation*} \Delta x = \frac{b-a}{m} \quad \quad \text{ and } \quad \quad \Delta y = \frac{d-c}{n} \end{equation*}
    Thus,
    \begin{equation*} \frac{1}{mn} = \frac{\Delta x \cdot \Delta y}{(b-a)(d-c)} = \frac{\Delta A}{A(R)}, \end{equation*}
    where \(A(R)\) denotes the area of the rectangle \(R\text{.}\) Then, the average value of the function \(f\) over \(R\text{,}\) \(f_{\operatorname{AVG}(R)}\text{,}\) is given by
    \begin{align*} f_{\operatorname{AVG}(R)} \amp = \lim_{m,n \to \infty} \frac{1}{mn} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*)\\ \amp = \lim_{m,n \to \infty} \frac{1}{A(R)} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \cdot \Delta A\\ \amp = \frac{1}{A(R)} \iint_R f(x,y) \, dA. \end{align*}
    Therefore, the double integral of \(f\) over \(R\) divided by the area of \(R\) gives us the average value of the function \(f\) on \(R\text{.}\) Finally, if \(f(x, y) \geq 0\) on \(R\text{,}\) we can interpret this average value of \(f\) on \(R\) as the height of the box with base \(R\) that has the same volume as the volume of the surface defined by \(f\) over \(R\text{.}\)
  • If the function being integrated is a density function, then integral measures how much of the thing being measured is in the region of integration. You can see a single variable calculus explanation of this in Recovering Position from Velocity and this will be explored in a multivariable setting in Section 12.4 and later applications.
    For example, if our function measures the density of some material on some plot of land, then the double integral of this function will measure the total amount of that material on the plot of land. The function (\(f(x,y)\)) will have units of mass (of the material) per unit area and the Riemann sum
    \begin{equation*} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \Delta A \end{equation*}
    will have units of mass. This idea is used for the laminar masses given in Section 12.4 and applies to many other settings including electric charge (which has the possibility of negative values for both the density and total amount).

Activity 12.1.3.
Let \(f(x,y) = x+2y\) and let \(R = [0,2] \times [1,3]\text{.}\)
(a)
Draw a picture of \(R\text{.}\) Partition \([0,2]\) into 2 subintervals of equal length and the interval \([1,3]\) into two subintervals of equal length. Draw these partitions on your picture of \(R\) and label the resulting subrectangles using the labeling scheme we established in the definition of a double Riemann sum.
(b)
For each \(i\) and \(j\text{,}\) let \((x_{ij}^*, y_{ij}^*)\) be the midpoint of the rectangle \(R_{ij}\text{.}\) Identify the coordinates of each \((x_{ij}^*, y_{ij}^*)\text{.}\) Draw these points on your picture of \(R\text{.}\)
(c)
Calculate the Riemann sum
\begin{equation*} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \cdot \Delta A \end{equation*}
using the partitions we have described. If we let \((x_{ij}^*, y_{ij}^*)\) be the midpoint of the rectangle \(R_{ij}\) for each \(i\) and \(j\text{,}\) then the resulting Riemann sum is called a midpoint sum.
(d)
Explain the meaning of the sum you just calculated using the preceding three interpretations.

Activity 12.1.4.
Let \(f(x,y) = \sqrt{4-y^2}\) on the rectangular domain \(R = [1,7] \times [-2,2]\) where we partition \([1,7]\) into 3 equal length subintervals and \([-2,2]\) into 2 equal length subintervals. A table of values of \(f\) at some points in \(R\) is given in Table 12.1.14, and a graph of \(f\) with the indicated partitions is shown in Figure 12.1.15.
Table 12.1.14. Table of values of \(f(x,y) = \sqrt{4-y^2}\text{.}\)
\(x \downarrow \backslash \, y \rightarrow\) \(-2\) \(-1\) \(0\) \(1\) \(2\)
\(1\) \(0\) \(\sqrt{3}\) \(2\) \(\sqrt{3}\) \(0\)
\(2\) \(0\) \(\sqrt{3}\) \(2\) \(\sqrt{3}\) \(0\)
\(3\) \(0\) \(\sqrt{3}\) \(2\) \(\sqrt{3}\) \(0\)
\(4\) \(0\) \(\sqrt{3}\) \(2\) \(\sqrt{3}\) \(0\)
\(5\) \(0\) \(\sqrt{3}\) \(2\) \(\sqrt{3}\) \(0\)
\(6\) \(0\) \(\sqrt{3}\) \(2\) \(\sqrt{3}\) \(0\)
\(7\) \(0\) \(\sqrt{3}\) \(2\) \(\sqrt{3}\) \(0\)
Figure 12.1.15.
(b)
Calculate the double Riemann sum using the given partition of \(R\) and the values of \(f\) in the upper right corner of each subrectangle.
(c)
Use geometry to calculate the exact value of \(\iint_R f(x,y) \, dA\) and compare it to your approximation. Describe one way we could obtain a better approximation using the given data.
We conclude this section with a list of properties of double integrals. Since similar properties are satisfied by single-variable integrals and the arguments for double integrals are essentially the same, we omit their justification.

Properties of Double Integrals.

Let \(f\) and \(g\) be continuous functions on a rectangle \(R = \{(x,y) : a \leq x \leq b, c \leq y \leq d\}\text{,}\) and let \(k\) be a constant. Then
  1. \(\iint_R (f(x,y) + g(x,y)) \, dA = \iint_R f(x,y) \, dA + \iint_R g(x,y) \, dA\text{.}\)
  2. \(\iint_R kf(x,y) \, dA = k \iint_R f(x,y) \, dA\text{.}\)
  3. If \(f(x,y) \geq g(x,y)\) on \(R\text{,}\) then \(\iint_R f(x,y) \, dA \geq \iint_R g(x,y) \, dA\text{.}\)

Subsection 12.1.5 Summary

  • Let \(f\) be a continuous function on a rectangle \(R = \{(x,y) : a \leq x \leq b, c \leq y \leq d\}\text{.}\) The double Riemann sum for \(f\) over \(R\) is created as follows.
    1. Partition the interval \([a, b]\) into \(m\) subintervals of equal length \(\Delta x = \frac{b-a}{m}\text{.}\) Let \(x_0\text{,}\) \(x_1\text{,}\) \(\ldots\text{,}\) \(x_m\) be the endpoints of these subintervals, where \(a = x_0\lt x_1\lt x_2 \lt \cdots \lt x_m = b\text{.}\)
    2. Partition the interval \([c, d]\) into \(n\) subintervals of equal length \(\Delta y = \frac{d-c}{n}\text{.}\) Let \(y_0\text{,}\) \(y_1\text{,}\) \(\ldots\text{,}\) \(y_n\) be the endpoints of these subintervals, where \(c = y_0\lt y_1\lt y_2 \lt \cdots \lt y_n = d\text{.}\)
    3. These two partitions create a partition of the rectangle \(R\) into \(mn\) subrectangles \(R_{ij}\) with opposite vertices \((x_{i-1},y_{j-1})\) and \((x_i, y_j)\) for \(i\) between \(1\) and \(m\) and \(j\) between \(1\) and \(n\text{.}\) These rectangles all have equal area \(\Delta A = \Delta x \cdot \Delta y\text{.}\)
    4. Choose a point \((x_{ij}^*, y_{ij}^*)\) in each rectangle \(R_{ij}\text{.}\)
    Then a double Riemann sum for \(f\) over \(R\) is given by
    \begin{equation*} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \cdot \Delta A. \end{equation*}
  • With terms defined as in the Double Riemann Sum, the double integral of \(f\) over \(R\) is
    \begin{equation*} \iint_R f(x,y) \, dA = \lim_{m,n \to \infty} \sum_{j=1}^n \sum_{i=1}^m f(x_{ij}^*, y_{ij}^*) \cdot \Delta A. \end{equation*}
  • Interpretations of the double integral \(\iint_R f(x,y) \, dA\) are:
    • The volume of the solids the graph of \(f\) bounds above the \(xy\)-plane over the rectangle \(R\) minus the volume of the solids the graph of \(f\) bounds below the \(xy\)-plane under the rectangle \(R\text{;}\)
    • Dividing the double integral of \(f\) over \(R\) by the area of \(R\) gives us the average value of the function \(f\) on \(R\text{.}\) If \(f(x, y) \geq 0\) on \(R\text{,}\) we can interpret this average value of \(f\) on \(R\) as the height of the box with base \(R\) that has the same volume as the volume of the surface defined by \(f\) over \(R\text{.}\)
    • If \(f(x,y)\) is the density of a substance over some area \(R\text{,}\) then the double integral of \(f\) over \(R\) will measure the total amount of the substance in \(R\text{.}\)

Exercises 12.1.6 Exercises

1.

Suppose \(f(x,y) = 25-x^{2}-y^{2}\) and \(R\) is the rectangle with vertices (0,0), (6,0), (6,4), (0,4). In each part, estimate \(\displaystyle \iint\limits_R f(x,y) \, dA\) using Riemann sums. For underestimates or overestimates, consistently use either the lower left-hand corner or the upper right-hand corner of each rectangle in a subdivision, as appropriate.
(a) Without subdividing \(R\text{,}\)
Underestimate =
Overestimate =
(b) By partitioning \(R\) into four equal-sized rectangles.
Underestimate =
Overestimate =

2.

Consider the solid that lies above the square (in the \(xy\)-plane) \(R = [0, 1] \times [0, 1]\text{,}\) and below the elliptic paraboloid \(z = 100 - x^2+ 6 xy - 2 y^2\text{.}\)
Estimate the volume by dividing \(R\) into 9 equal squares and choosing the sample points to lie in the midpoints of each square.

3.

Let \(R\) be the rectangle with vertices \((0,0)\text{,}\) \((2,0)\text{,}\) \((2,2)\text{,}\) and \((0,2)\) and let \(f(x,y) = \sqrt{0.25xy}\text{.}\)
(a) Find reasonable upper and lower bounds for \(\int_{R}f\,dA\) without subdividing \(R\text{.}\)
upper bound =
lower bound =
(b) Estimate \(\int_{R}f\,dA\) three ways: by partitioning \(R\) into four subrectangles and evaluating \(f\) at its maximum and minimum values on each subrectangle, and then by considering the average of these (over and under) estimates.
overestimate: \(\int_{R}f\,dA \approx\)
underestimate: \(\int_{R}f\,dA \approx\)
average: \(\int_{R}f\,dA \approx\)

4.

Using Riemann sums with four subdivisions in each direction, find upper and lower bounds for the volume under the graph of \(f(x,y) = 4+xy\) above the rectangle \(R\) with \(0\le x\le 1,\quad 0\le y \le 5\text{.}\)
upper bound =
lower bound =

5.

Consider the solid that lies above the square (in the xy-plane) \(R = [0, 2] \times [0, 2]\text{,}\)
and below the elliptic paraboloid \(z = 36 - x^{2} - 2y^2\text{.}\)
(A) Estimate the volume by dividing R into 4 equal squares and choosing the sample points to lie in the lower left hand corners.
(B) Estimate the volume by dividing R into 4 equal squares and choosing the sample points to lie in the upper right hand corners..
(C) What is the average of the two answers from (A) and (B)?

6.

The figure below shows contours of \(g(x,y)\) on the region \(R\text{,}\) with \(5 \le x\le 11\) and \(2 \le y\le 8\text{.}\)
Using \(\Delta x = \Delta y =2\text{,}\) find an overestimate and an underestimate for \(\int_R g(x,y)\, dA\text{.}\)
Overestimate =
Underestimate =

7.

The figure below shows the distribution of temperature, in degrees C, in a 5 meter by 5 meter heated room.
Using Riemann sums, estimate the average temperature in the room.
average temperature =

8.

Values of \(f(x,y)\) are given in the table below. Let \(R\) be the rectangle \(1 \leq x \leq 1.6, 2 \leq y \leq 3.2\text{.}\) Find a Riemann sum which is a reasonable estimate for \(\int_R f(x,y) \, da\) with \(\Delta x = 0.2\) and \(\Delta y = 0.4\text{.}\) Note that the values given in the table correspond to midpoints.
\begin{equation*} \begin{array}{|c || c|c|c|} \hline y \backslash x \amp 1.1 \amp 1.3 \amp 1.5 \\ \hline \hline 2.2 \amp 4 \amp 0 \amp -5 \\ \hline 2.6 \amp -3 \amp 0 \amp 8 \\ \hline 3.0 \amp 6 \amp 6 \amp -4 \\ \hline \end{array} \end{equation*}
\(\int_R f(x,y) \, da \approx\)

9.

Values of \(f(x,y)\) are shown in the table below.
\(x = 3\) \(x = 3.2\) \(x = 3.4\)
\(y = 5\) 7 8 11
\(y = 5.4\) 6 7 8
\(y = 5.8\) 5 6 17
Let \(R\) be the rectangle \(3 \leq x \leq 3.4\text{,}\) \(5 \leq y \leq 5.8\text{.}\) Find the values of Riemann sums which are reasonable over- and under-estimates for \(\int_R f(x,y) \,dA\) with \(\Delta x=0.2\) and \(\Delta y=0.4\text{.}\)
over-estimate:
under-estimate:

10.

The temperature at any point on a metal plate in the \(xy\) plane is given by \(T(x,y) = 100-4x^2 - y^2\text{,}\) where \(x\) and \(y\) are measured in inches and \(T\) in degrees Celsius. Consider the portion of the plate that lies on the rectangular region \(R = [1,5] \times [3,6]\text{.}\)
  1. Estimate the value of \(\iint_R T(x,y) \, dA\) by using a double Riemann sum with two subintervals in each direction and choosing \((x_i^*, y_j^*)\) to be the point that lies in the upper right corner of each subrectangle.
  2. Determine the area of the rectangle \(R\text{.}\)
  3. Estimate the average temperature, \(T_{\operatorname{AVG}(R)}\text{,}\) over the region \(R\text{.}\)
  4. Do you think your estimate in (c) is an over- or under-estimate of the true temperature? Why?

11.

Let \(f\) be a function of independent variables \(x\) and \(y\) that is increasing in both the positive \(x\) and \(y\) directions on a rectangular domain \(R\text{.}\) For each of the following situations, determine if the double Riemann sum of \(f\) over \(R\) is an overestimate or underestimate of the double integral \(\iint_R f(x,y) \, dA\text{,}\) or if it impossible to determine definitively. Provide justification for your responses.
  1. The double Riemann sum of \(f\) over \(R\) where \(f\) is evaluated at the lower left point of each subrectangle.
  2. The double Riemann sum of \(f\) over \(R\) where \(f\) is evaluated at the upper right point of each subrectangle.
  3. The double Riemann sum of \(f\) over \(R\) where \(f\) is evaluated at the midpoint of each subrectangle.
  4. The double Riemann sum of \(f\) over \(R\) where \(f\) is evaluated at the lower right point of each subrectangle.

12.

The wind chill, as frequently reported, is a measure of how cold it feels outside when the wind is blowing. In Table 12.1.16, the wind chill \(w=w(v,T)\text{,}\) measured in degrees Fahrenheit, is a function of the wind speed \(v\text{,}\) measured in miles per hour, and the ambient air temperature \(T\text{,}\) also measured in degrees Fahrenheit. Approximate the average wind chill on the rectangle \([5,35] \times [-20,20]\) using 3 subintervals in the \(v\) direction, 4 subintervals in the \(T\) direction, and the point in the lower left corner in each subrectangle.
Table 12.1.16. Wind chill as a function of wind speed and temperature.
\(v \backslash T\) \(-20\) \(-15\) \(-10\) \(-5\) \(0\) \(5\) \(10\) \(15\) \(20\)
\(5\) \(-34\) \(-28\) \(-22\) \(-16\) \(-11\) \(-5\) \(1\) \(7\) \(13\)
\(10\) \(-41\) \(-35\) \(-28\) \(-22\) \(-16\) \(-10\) \(-4\) \(3\) \(9\)
\(15\) \(-45\) \(-39\) \(-32\) \(-26\) \(-19\) \(-13\) \(-7\) \(0\) \(6\)
\(20\) \(-48\) \(-42\) \(-35\) \(-29\) \(-22\) \(-15\) \(-9\) \(-2\) \(4\)
\(25\) \(-51\) \(-44\) \(-37\) \(-31\) \(-24\) \(-17\) \(-11\) \(-4\) \(3\)
\(30\) \(-53\) \(-46\) \(-39\) \(-33\) \(-26\) \(-19\) \(-12\) \(-5\) \(1\)
\(35\) \(-55\) \(-48\) \(-41\) \(-34\) \(-27\) \(-21\) \(-14\) \(-7\) \(0\)

13.

Consider the box with a sloped top that is given by the following description: the base is the rectangle \(R = [0,4] \times [0,3]\text{,}\) while the top is given by the plane \(z = p(x,y) = 20 - 2x - 3y\text{.}\)
  1. Estimate the value of \(\iint_R p(x,y) \, dA\) by using a double Riemann sum with four subintervals in the \(x\) direction and three subintervals in the \(y\) direction, and choosing \((x_i^*, y_j^*)\) to be the point that is the midpoint of each subrectangle.
  2. What important quantity does your double Riemann sum in (a) estimate?
  3. Suppose it can be determined that \(\iint_R p(x,y) \, dA = 138\text{.}\) What is the exact average value of \(p\) over \(R\text{?}\)
  4. If you wanted to build a rectangular box (with the same base) that has the same volume as the box with the sloped top described here, how tall would the rectangular box have to be?