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Active Calculus - Multivariable

Preview Activity 11.2.1.
In this Preview Activity, we will consider several ideas related to limits of single-variable functions by working with tables, graphs, and the algebraic forms of these functions.
(a)
Let \(f\) defined by \(f(x) = 3-x\text{.}\) Complete the table below.
\(x\)   \(-0.2\)     \(-0.1\)     \(-0.01\)     \(0.01\)     \(0.1\)     \(0.2\)  
\(f(x)\)
(b)
Write a sentence about what the table in part a suggests regarding \(\displaystyle\lim_{x\to 0}f(x)\text{.}\)
(c)
Write a couple of sentences to explain how your values in the table in part a and \(\displaystyle\lim_{x\to 0}f(x)\) are demonstrated in the graph below.
(d)
Let \(\displaystyle g(x) = \frac{x}{|x|}\text{.}\) Fill in the blanks of the table below with the appropriate outputs of \(g\) for values near \(x = 0\text{.}\) Note that \(g\) is not defined at \(x=0\text{.}\)
\(x\)   \(-0.1\)     \(-0.01\)     \(-0.001\)     \(0.001\)     \(0.01\)     \(0.1\)  
\(g(x)\)
(e)
Write a few sentences about what the values in the table in part d suggests about \(\displaystyle\lim_{x \to 0}g(x)\text{.}\)
(f)
Write a couple of sentences to explain how your values in the table in part d and
\begin{equation*} \lim_{x\to 0} g(x) \end{equation*}
are demonstrated in the plot below.
(g)
Let \(\displaystyle h(x)=\frac{1-x^2}{x+1}\text{.}\) At what point(s) is \(h\) undefined?
(h)
Show that the limit as \(x\) goes to \(-1\) of \(h(x)\) exists. Write a sentence or two about why \(h(-1)\) does not exist but the limit as \(x\) goes to \(-1\) does exist.
(i)
Graph \(h(x)\) for a region around \(x=-1\) and explain how this graph relates to your answer to the previous two parts.