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Active Calculus - Multivariable

Activity 11.9.4.
While the quantity of a product demanded by consumers is often a function of the price of the product, the demand for a product may also depend on the price of other products. For instance, the demand for blue jeans at a clothing store may be affected not only by the price of the jeans themselves, but also by the price of khakis.
Suppose we have two goods whose respective prices are \(p_1\) and \(p_2\text{.}\) The demand for these goods, \(q_1\) and \(q_2\text{,}\) depend on the prices as
\begin{align} q_1 \amp = 150 - 2p_1 - p_2 \tag{11.9.1}\\ q_2 \amp = 200 - p_1 - 3p_2 \tag{11.9.2} \end{align}
The seller would like to set the prices \(p_1\) and \(p_2\) in order to maximize revenue. We will assume that the seller meets the full demand for each product. Thus, if we let \(R\) be the revenue obtained by selling \(q_1\) items of the first good at price \(p_1\) per item and \(q_2\) items of the second good at price \(p_2\) per item, we have
\begin{equation*} R = p_1q_1 + p_2q_2. \end{equation*}
We can then write the revenue as a function of just the two variables \(p_1\) and \(p_2\) by using Equations (11.9.1) and (11.9.2), giving us
\begin{align*} R(p_1,p_2) \amp = p_1(150 - 2p_1 - p_2) + p_2(200 - p_1 - 3p_2)\\ \amp = 150p_1 + 200p_2 - 2p_1p_2 -2p_1^2 - 3p_2^2. \end{align*}
A graph of \(R\) as a function of \(p_1\) and \(p_2\) is shown in Figure 11.9.13.
Figure 11.9.13. A plot of the revenue function \(R(p_1,p_2)\)
(a)
Find all critical points of the revenue function, \(R\text{.}\)
Hint.
You should obtain a system of two equations in two unknowns which can be solved by elimination or substitution.
(b)
Apply the Second Derivative Test to determine the type of any critical point(s).
(c)
Where should the seller set the prices \(p_1\) and \(p_2\) to maximize the revenue?