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Active Calculus - Multivariable

Activity 12.8.5.
Let \(D'\) be the region in the \(xy\)-plane bounded by the lines \(y=0\text{,}\) \(x=0\text{,}\) and \(x+y=1\text{.}\) We will evaluate the double integral
\begin{equation} \iint_{D'} \sqrt{x+y}(x-y)^2 \, dA\tag{12.8.4} \end{equation}
with a change of variables.
(a)
Sketch the region \(D'\) in the \(xy\)-plane.
(b)
We would like to make a substitution that makes the integrand easier to antidifferentiate. Let \(s = x+y\) and \(t = x-y\text{.}\) Explain why this should make antidifferentiation easier by making the corresponding substitutions and writing the new integrand in terms of \(s\) and \(t\text{.}\)
(c)
Solve the equations \(s = x+y\) and \(t = x-y\) for \(x\) and \(y\text{.}\) (Doing so determines the standard form of the transformation, since we will have \(x\) as a function of \(s\) and \(t\text{,}\) and \(y\) as a function of \(s\) and \(t\text{.}\))
(d)
To actually execute this change of variables, we need to know the \(st\)-region \(D\) that corresponds to the \(xy\)-region \(D'\text{.}\)
  1. What \(st\) equation corresponds to the \(xy\) equation \(x+y=1\text{?}\)
  2. What \(st\) equation corresponds to the \(xy\) equation \(x=0\text{?}\)
  3. What \(st\) equation corresponds to the \(xy\) equation \(y=0\text{?}\)
  4. Sketch the \(st\) region \(D\) that corresponds to the \(xy\) domain \(D'\text{.}\)
(e)
Make the change of variables indicated by \(s = x+y\) and \(t = x-y\) in the double integral (12.8.4) and set up an iterated integral in \(st\) variables whose value is the original given double integral. Finally, evaluate the iterated integral.