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Section 3.8 Motivating Activity

Activity 3.8.1.

Let’s look at the vector \(\vec{w}=\colvec{7 \\-2}\) as a vector in \(\mathbb{R}^2\text{.}\)

(a)

How much does \(\vec{w}=\colvec{7 \\-2}\) move horizontally?

(b)

How much does \(\vec{w}=\colvec{7 \\-2}\) move vertically?

(c)

Calculate the dot product of \(\vec{w}=\colvec{7 \\-2}\) with \(\colvec{1\\0}\text{.}\) How does this relate to your previous answers?

(d)

Calculate the dot product of \(\vec{w}=\colvec{7 \\-2}\) with \(\colvec{0\\1}\text{.}\) How does this relate to your previous answers?

(e)

How can you write \(\vec{w}=\colvec{7 \\-2}\) as a linear combination of \(\colvec{1\\0}\) and \(\colvec{0\\1}\text{?}\)

(f)

How much does \(\vec{w}=\colvec{7 \\-2}\) move in the \(\colvec{1\\1}\) direction?

(g)

How much does \(\vec{w}=\colvec{7 \\-2}\) move in the \(\colvec{-1\\1}\) direction?

(h)

Calculate the dot product of \(\vec{w}=\colvec{7 \\-2}\) with \(\colvec{1\\1}\text{.}\) How does this relate to your previous answers?

(i)

Calculate the dot product of \(\vec{w}=\colvec{7 \\-2}\) with \(\colvec{-1\\1}\text{.}\) How does this relate to your previous answers?

(j)

How can you write \(\vec{w}=\colvec{7 \\-2}\) as a linear combination of \(\colvec{1\\1}\) and \(\colvec{-1\\1}\text{?}\)

(k)

How much does \(\vec{w}=\colvec{7 \\-2}\) move in the \(\colvec{1\\1}\) direction?

(l)

How much does \(\vec{w}=\colvec{7 \\-2}\) move in the \(\colvec{1\\0}\) direction?

(m)

Calculate the dot product of \(\vec{w}=\colvec{7 \\-2}\) with \(\colvec{1\\1}\text{.}\) How does this relate to your previous answers?

(n)

Calculate the dot product of \(\vec{w}=\colvec{7 \\-2}\) with \(\colvec{1\\0}\text{.}\) How does this relate to your previous answers?

(o)

How can you write \(\vec{w}=\colvec{7 \\-2}\) as a linear combination of \(\colvec{1\\1}\) and \(\colvec{1\\0}\text{?}\)

(p)

What is different about the different sets we considered to span \(\mathbb{R}^2\) in this activity? Be specific about what aspects will make answering the linear combination question easier to answer.